Back to top not working

Hi: a little problem. The back to top link in a k2 item, doesn't goes to top.
I try this from a clean installation of gk_news_quickstart_J!3.zip

http://www.club-pescadores.com.ar/subdo ... he-nation#

Hi, it doesn't work, because be default is linked to article title, which is not link in your case anymore.
So I suggest to hide this "up" button

.itemBackToTop {display:none;}

Sorry: I d'ont understand ... in my case i'm using k2 ... back to top is only for joomla native articles ?

Thanks !

back link is generated by K2 items, and looks that it not working well.
This may be a K2 issue.
--
In theory I can fix, but it will be based on php file edition.

Thinking the same ... modifying:
html\com_k2\templates\templates\default\item.php with a javascript call. I'll make some research... thanks !

Easy way,
just replace dynamic link with static taken from header ID section, this same effect.

In this line al item.php ?
<a class="itemBackToTop" href="<?php echo $this->item->link; ?>#"> <?php echo JText::_('K2_BACK_TO_TOP'); ?> </a>

I guess, it should be it.

Hi: i make some changes... seems to be working ok and anything is broken. If you take a look and it's ok, perhaps this are my two cents

Regards,
Leandro

Test link: http://www.club-pescadores.com.ar/insti ... storiaclub

_________________
Two changes:

1) In mytemplate\html\com_k2\templates\default\item.php

Line:
<a class="itemBackToTop" href="<?php echo $this->item->link; ?>#"> <?php echo JText::_('K2_BACK_TO_TOP'); ?> </a>

Change:
<a class="itemBackToTop irArriba" href="<?php echo $this->item->link; ?>#"> <?php echo JText::_('K2_BACK_TO_TOP'); ?> </a>


2) In mytemplate\layouts\default.php

In the next script, add the bolded line:

<script>
jQuery(document).ready(function(){
// Target your .container, .wrapper, .post, etc.
jQuery("body").fitVids();

jQuery(".irArriba").click(function() {
window.scrollTo(0,0);
});
});
</script>

Try only this small change:

<a class="itemBackToTop" href="#gkPageTop"> <?php echo JText::_('K2_BACK_TO_TOP'); ?> </a>

Thanks ! Yours is a better solution.